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0.006x^2+0.6x-6.6=0
a = 0.006; b = 0.6; c = -6.6;
Δ = b2-4ac
Δ = 0.62-4·0.006·(-6.6)
Δ = 0.5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.6)-\sqrt{0.5184}}{2*0.006}=\frac{-0.6-\sqrt{0.5184}}{0.012} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.6)+\sqrt{0.5184}}{2*0.006}=\frac{-0.6+\sqrt{0.5184}}{0.012} $
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